MCQ
$A$ rectangular loop with a sliding connector of length $10\, cm$ is situated in uniform magnetic field perpendicular to plane of loop. The magnetic induction is $0.1$ tesla and resistance of connector $(R)$ is $1\, ohm$. The sides $AB$ and $CD$ have resistances $2$ $ohm$ and $3$ $ohm$ respectively. Find the current in the connector during its motion with constant velocity one $metre/sec.$
  • A
    $\frac{1}{{110}} A$
  • $\frac{1}{{220}} A$
  • C
    $\frac{1}{{55}} A$
  • D
    $\frac{1}{{440}} A$

Answer

Correct option: B.
$\frac{1}{{220}} A$
b
$e=B l v=0.1 \times 0.1 \times 1$

$e=0.01$ volt

$I=\frac{0.01}{1+\frac{6}{5}}=\frac{0.01}{2.2}=\frac{1}{220} A m p$

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