Question
A rectangular tank 15m long and 11m broad is required to receive entire liquid contents from a fully cylindrical tank of internal diameter 21m and length 5m. Find the least height of the tank that will serve the purpose.

Answer

Suppose height of the rectangular tank is equal to h.
Length of the tank = 15m
Breadth of the tank = 11m
Further,
length of cylindrical tank = 5m
Radius of cylindrical tank $=\frac{21}{2}\text{m}$
To find out the least height of the tank, equate the volumes of two tanks.
$15\times11\times\text{h}\times\pi\Big(\frac{21}{2}\Big)^2\times5$
$\Rightarrow\text{h}=\frac{22}{7}\times\frac{21}{2}\times\frac{21}{2}\times\frac{5}{15}\times\frac{1}{11}$
$\Rightarrow\text{h}=\frac{21}{2}$
$\Rightarrow\text{h}=10.5$
Hence, the least height of the tank is equal to 10.5

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