A resistance R and a capacitor C are connected in series to a source $\text{V}=\text{V}_0\sin\omega\text{t}.$
Find:
Find:
- The peak value of the voltage across the (i) resistance and (ii) capacitor.
- The phase difference between the applied voltage and current. Which of them is ahead?
CBSE 55-1-1 PAPER SET 2020
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$\text{I}_0=\frac{\text{V}_0}{\sqrt{\text{R}^2+\text{X}^2_\text{c}}}$
- Peak Voltage Across.
- Resistance R is $\text{V}_\text{R}=\text{I}_0\text{R}=\frac{\text{V}_0\text{R}}{\sqrt{\text{R}^2+\text{X}^2_\text{C}}}$
- Capacitor C is $\text{V}_\text{C}=\text{I}_0\text{X}_\text{C}=\frac{\text{I}_0\text{X}_\text{C}}{\sqrt{\text{R}^2+\text{X}^2_\text{C}}}$
$\phi=\tan^{-1}\Big(\frac{\text{V}_\text{C}}{\text{V}_\text{R}}\Big)=\tan^{-1}\Big(\frac{\text{X}_\text{C}}{\text{R}}\Big)=$ Phase difference between V & I is ahead of V.
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