A resistor of 8 ohms is connected in parallel with another resistor X. The resultant resistance of the combination is 4.8 ohms. What is the value of the resistor X?
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Given:
A resistor of 8ohm is connected in parallel with a resistor of x.
And resultant is 4.8.
Then X = ?
We know that for parallel case
$\frac{1}{\text{R}}=\frac{1}{\text{R}_1}+\frac{1}{\text{X}}$
$\frac{1}{4.8}=\frac{1.8}{}+\frac{1}{\text{x}}$
$\frac{1}{4.8}-\frac{1}{8}=\frac{1}{\text{x}}$
After solving we get that
X = 12 ohms.
A resistor of 8ohm is connected in parallel with a resistor of x.
And resultant is 4.8.
Then X = ?
We know that for parallel case
$\frac{1}{\text{R}}=\frac{1}{\text{R}_1}+\frac{1}{\text{X}}$
$\frac{1}{4.8}=\frac{1.8}{}+\frac{1}{\text{x}}$
$\frac{1}{4.8}-\frac{1}{8}=\frac{1}{\text{x}}$
After solving we get that
X = 12 ohms.
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