MCQ
A rubber cord $10 m$ long is suspended vertically. How much does it stretch under its own weight (Density of rubber is $1500 kg / m , Y=$ $5 \times 10^{\circ} N / m , g =10 m / s$ )
  • $15 \times 10^{-4} m$
  • B
    $7.5 \times 10^{-6} m$
  • C
    $12 \times 10^{-9} m$
  • D
    $25 \times 10^{-7}m$

Answer

Correct option: A.
$15 \times 10^{-4} m$
$l=\frac{L^2 d g}{2 Y}=\frac{(10)^2 \times 1500 \times 10}{2 \times 5 \times 10^8}=15 \times 10^{-4} \mathrm{~m}$

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