A sample of a liquid has an initial volume of $1.5\,L$ . The volume is reduced by $0.2\,mL$ , when the pressure increases by $140\,kP$ . What is the bulk modulus of the liquid
A$3.05 \times 10^9\,Pa$
B$1.05 \times 10^9\,Pa$
C$1.05 \times 10^7\,Pa$
D$1.05 \times 10^{11}\,Pa$
Medium
Download our app for free and get started
B$1.05 \times 10^9\,Pa$
b $B=-\frac{\Delta P}{\Delta V / V}=-\frac{V \Delta P}{\Delta V}=-\frac{1.5 \times 140 \times 10^{3}}{-0.2 \times 10^{-3}}$
$=1.05 \times 10^{9} \mathrm{Pa}$
Download our app
and get started for free
Experience the future of education. Simply download our apps or reach out to us for more information. Let's shape the future of learning together!No signup needed.*
When a rubber ball is taken to the bottom of a sea of depth $1400 \,m$, its volume decreases by $2 \%$. The Bulk modulus of rubber ball is .................. $\times 10^8 N / m ^2$ [density of water is $1 \,g cc$ and $g=10 \,m / s ^2$ ]
Young's moduli of the material of wires $A$ and $B$ are in the ratio of $1: 4$, while its area of cross sections are in the ratio of $1: 3$. If the same amount of load is applied to both the wires, the amount of elongation produced in the wires $A$ and $B$ will be in the ratio of
A uniformly tapering conical wire is made from a material of Young's modulus $Y$ and has a normal, unextended length $L.$ The radii, at the upper and lower ends of this conical wire, have values $R$ and $3R,$ respectively. The upper end of the wire is fixed to a rigid support and a mass $M$ is suspended from its lower end. The equilibrium extended length, of this wire, would equal
A $5\, m$ long aluminium wire ($Y = 7 \times {10^{10}}N/{m^2})$ of diameter $3\, mm$ supports a $40\, kg$ mass. In order to have the same elongation in a copper wire $(Y = 12 \times {10^{10}}N/{m^2})$ of the same length under the same weight, the diameter should now be, in $mm.$