MCQ
A schematic plot of versus inverse of temperature for a reaction is shown below The reaction must be


- ✓Exothermic
- BEndothermic
- COne with negligible enthalpy change
- DHighly spontaneous at ordinary temperature

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$\begin{array}{*{20}{c}}
{\,\,C{H_3}\,\,\,\,\,\,\,\,\,\,\,} \\
{|\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,} \\
{C{H_3} - C - CH = C{H_2}} \\
{|\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,} \\
{\,\,C{H_3}\,\,\,\,\,\,\,\,\,\,\,}
\end{array}\xrightarrow[{2.\,KOH - EtOH,\,heat}]{{1.\,HBr}}$
The major end product formed is :-