MCQ
A screw gauge of pitch $0.5\,mm$ is used to measure the diameter of uniform wire of length $6.8\,cm$, the main scale reading is $1.5\,mm$ and circular scale reading is $7$. The calculated curved surface area of wire to appropriate significant figures is $......cm^2$ . [Screw gauge has $50$ divisions on the circular scale]
  • A
    $6.8$
  • $3.4$
  • C
    $3.9$
  • D
    $2.4$

Answer

Correct option: B.
$3.4$
b
$ L.C.=\frac{P}{N}=\frac{0.5\,mm}{50}=0.01\,mm$

Length of wire $=6.8 cm$

Diameter of wire $=1.5\,mm +7 \times L.C$

$=1.5\, mm +7 \times .01=1.57\,mm$

Curved surface area $=\pi Dl$

$=3.14 \times 6.8 \times 1.57 \times 10^{-1} cm^{2}$

$=3.352\,cm ^{2}=3.4\,cm ^{2}$

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