For second harmonic, wavelength $\left(\lambda_{2}\right)$ of the standing waves set up on the corresponds to the $n=2$
Thus, $\lambda_{n}=\frac{2 l}{n}$
$\Rightarrow \lambda_{2}=\frac{2 l}{2}=l$
This shows that we have an antinode at $l / 2$
This shows that we have an node at $l / 4$
