A cyclist on a level road takes a sharp circular turn of radius $3 \;m \;\left( g =10 \;ms ^{-2}\right)$. If the coefficient of static friction between the cycle tyres and the road is $0.2$, at which of the following speeds will the cyclist not skid while taking the turn?
NEET 2017, Medium
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The maximum speed at which the cyclist will not skid is,
$v_{m}=\sqrt{\mu r g}=\sqrt{0.2 \times 3 \times 10}=2.45 m / s$
$=\frac{2.45 \times 60 \times 60}{1000} km / h =8.82 km \cdot h^{-1}$
Among the given options $7.2\; km \cdot h^{-1}$ is less than this.
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