Question
A simple harmonic motion is described by a = -16x where a → acceleration, x → displacement in m. What is the time period?

Answer

For S.H.M., $\text{a}=-\omega^2\text{x}$ Comparing with $\text{a}=-16\text{x}$$\because\omega^2=16\Rightarrow\omega=\frac{2\pi}{\text{T}}=\sqrt{16}=4$
$\therefore\text{T}=\frac{\pi}{2}\text{ second}$

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