A simple pendulum is taken from the equator to the pole. Its period
A
Decreases
B
Increases
C
Remains the same
D
Decreases and then increases
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A
Decreases
a (a)As we go from equator to pole the value of g increases. Therefore time period of simple pendulum $\left( {T \propto \frac{1}{{\sqrt g }}} \right)$ decreases.
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