A simple pendulum oscillates freely between points A and B. We no… - Vidyadip

MCQ

A simple pendulum oscillates freely between points $A$ and $B$. We now put a peg (nail) at the point $C$ as shown in above figure. As the pendulum moves from $A$ to the right, the string will bend at $C$ and the pendulum will go to its extreme point $D$. Ignoring friction, the point $D$

✓
will lie on the line $A B$
B
will lie above the line $A B$
C
will lie below the line $A B$
D
will coincide with $B$

✓

Answer

Correct option: A.

will lie on the line $A B$

a
(a)

Total length of a pendulum remains same, so extreme point $D$ lies on the line $A B$, as shown below.

This can be proved by applying energy conservation between extreme positions $A$ and $D$ (its given friction is abscent),

$K_A+U_A=K_B+U_B=K_D+U_D$

$\Rightarrow 0+U_A=0+U_B=0+U_D$

$\Rightarrow U_A=U_B=U_D \Rightarrow h_A=h_B=h_D$

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