A simple pendulum with iron bob has a time period $T$. The bob is now immersed in a non-viscous liquid and oscillated. If the density of liquid is $\frac{1}{12}$ th that of iron, then new time period will be
  • A$T \sqrt{\frac{8}{7}}$
  • B$T \sqrt{\frac{12}{13}}$
  • C$T \sqrt{\frac{12}{11}}$
  • D$T \sqrt{\frac{6}{5}}$
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