${T}_{0}$ is the time period of a simple pendulum at a place. If the length of the pendulum is reduced to $\frac{1}{16}$ times of its initial value, the modified time
JEE MAIN 2021, Easy
Download our app for free and get startedPlay store
Time period of a simple pendulum

${T}_{0}=2 \pi \sqrt{\frac{\ell}{{g}}}$

New time period ${T}=\sqrt[2 \pi]{\frac{\ell / 16}{{g}}}=\frac{2 \pi}{4} \sqrt{\frac{\ell}{{g}}}$

${T}=\frac{{T}_{0}}{4}$

art

Download our app
and get started for free

Experience the future of education. Simply download our apps or reach out to us for more information. Let's shape the future of learning together!No signup needed.*

Similar Questions

  • 1
    A block of mass $m$ is at rest on an another block of same mass as shown in figure. Lower block is attached to the spring, then the maximum amplitude of motion so that both the block will remain in contact is
    View Solution
  • 2
    The displacement equations of two interfering waves are given by

    $y_1  =10 \sin \left(\omega t+\frac{\pi}{3}\right) cm$

    $y_2 =5[\sin (\omega t)+\sqrt{3} \cos \omega t] \;cm$ respectively.

    The amplitude of the resultant wave is $.............cm$.

    View Solution
  • 3
    A simple pendulum of length $l$ and mass $m$ of the bob is suspended in a car that is travelling with a constant speed $v$ around a circular path of radius $R$. If the pendulum undergoes oscillations with small amplitude about its equilibrium position, the frequency of its oscillations will be
    View Solution
  • 4
    An assembly of identical spring-mass systems is placed on a smooth horizontal surface as shown. At this instant, the springs are relaxed. The left mass is displaced to the/left and theiright mass is displaced to the right by same distance and released. The resulting collision is elastic. The time period of the oscillations of system is
    View Solution
  • 5
    A pendulum with time period of $1\, s$ is losing energy due to damping. At certain time its energy is $45\, J$. If after  completing $15\,oscillations$ , its energy has become $15\, J$, its damping constant (in $s^{-1}$ ) is
    View Solution
  • 6
    A simple pendulum of length $l$ is made to oscillate with an amplitude of $45$ degrees. The acceleration due to gravity is $g$. Let $T_0=2 \pi \sqrt{l / g}$. The time period of oscillation of this pendulum will be
    View Solution
  • 7
    The resultant of two rectangular simple harmonic motions of the same frequency and equal amplitudes but differing in phase by $\frac{\pi }{2}$ is
    View Solution
  • 8
    Two massless springs with spring constants $2\,k$ and $2\,k$, carry $50\, g$ and $100 \,g$ masses at their free ends. These two masses oscillate vertically such that their maximum velocities are equal. Then, the ratio of their respective amplitudes will be
    View Solution
  • 9
    An $LCR$ circuit is equivalent to a damped pendulum. In an $LCR$ circuit the capacitor is charged to $Q_0$ and then connected to the $L$ and $R$ as shown below.

    If a student plots graphs of the square of maximum charge $( Q_{Max}  ^2 )$ on the capacitor with time$(t)$ for two different values $L_1$ and $L_2 (L_1 > L_2)$ of $L$ then which of the following represents this graph correctly? (plots are schematic and not drawn to scale)

    View Solution
  • 10
    A stationary tuning fork is in resonance with an air column in a pipe. If the tuning fork is moved with a speed of $2 ms ^{-1}$ in front of the open end of the pipe and parallel to it, the length of the pipe should be changed for the resonance to occur with the moving tuning fork. If the speed of sound in air is $320 ms ^{-1}$, the smallest value of the percentage change required in the length of the pipe is. . . . . .
    View Solution