MCQ
A small block slides down on a smooth inclined plane, starting from rest at time $t=0 .$ Let $S_{n}$ be the distance travelled by the block in the interval $\mathrm{t}=\mathrm{n}-1$ to $\mathrm{t}=\mathrm{n} .$ Then, the ratio $\frac{\mathrm{S}_{\mathrm{n}}}{\mathrm{S}_{\mathrm{n}+1}}$ is
  • A
    $\frac{2 n-1}{2 n}$
  • $\frac{2 n-1}{2 n+1}$
  • C
    $\frac{2 n+1}{2 n-1}$
  • D
    $\frac{2 n}{2 n-1}$

Answer

Correct option: B.
$\frac{2 n-1}{2 n+1}$
b
$\frac{s_{n}}{S_{n+1}}=\frac{\frac{a}{2}(2 n-1)}{\frac{a}{2}(2(n+1)-1)}=\frac{2 n-1}{2 n+2-1}=\frac{2 n-1}{2 n+1}$

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