a
Velocity of ball when it reaches to surface of liquid
$\mathrm{a}=\frac{1000 \mathrm{gV}-500 \mathrm{gV}}{500 \mathrm{V}}$
where $V$ is the volume of the ball.
$a=10 \mathrm{m} / \mathrm{sec}^{2}$
apply $\mathrm{v}=\mathrm{u}+\mathrm{at}$
$\Rightarrow 0=\sqrt{2 g h}-10 t$
$\Rightarrow \sqrt{2 g h}=10 \times(2)$
$\Rightarrow 2 \times 10 \times h=400$
$\Rightarrow \mathrm{h}=20\, \mathrm{m}$ Ans
