MCQ
The adjoining diagram shows the velocity versus time plot for a particle. The work done by the force on the particle is positive from
- ✓$A$ to $B$
- B$B$ to $C$
- C$C$ to $D$
- D$D$ to $E$
✓
Answer
Correct option: A.
$A$ to $B$
a
(a)From the graph it is clear that force is acting on the particle in the region $AB$ and due to this force kinetic energy (velocity) of the particle increases. So the work done by the force is positive.
(a)From the graph it is clear that force is acting on the particle in the region $AB$ and due to this force kinetic energy (velocity) of the particle increases. So the work done by the force is positive.
Need a full question paper?
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.
Explore more
Similar questions
Meena applies the front brakes, while riding on her bicycle along a flat road. The force that slows her bicycle is provided by the
Two moving coil meters $M_1$ and $M_2$ having the following particulars :-
$R_1 = 10\,\Omega , N_1 = 30, A_1 = 3.6\times10^{-3}\, m^2, B_1 = 0.25\, T$
$R_2 = 14\,\Omega , N_2 = 42, A_2 = 1.8\times10^{-3}\, m^2, B_2 = 0.50\, T$
(The spring constants are identical for the two meters). Determine the ratio of voltage sensitivity of $M_2$ and $M_1$
→$R_1 = 10\,\Omega , N_1 = 30, A_1 = 3.6\times10^{-3}\, m^2, B_1 = 0.25\, T$
$R_2 = 14\,\Omega , N_2 = 42, A_2 = 1.8\times10^{-3}\, m^2, B_2 = 0.50\, T$
(The spring constants are identical for the two meters). Determine the ratio of voltage sensitivity of $M_2$ and $M_1$
A force defined by $F=\alpha t^2+\beta t$ acts on a particle at a given time $t$. The factor which is dimensionless, if $\alpha$ and $\beta$ are constants, is:
→A plane electromagnetic wave propagating along y-direction can have the following pair of electric field $(\vec{E} )$ and magnetic field $(\overrightarrow{ B })$ components.
→A body of mass $2\, kg$ is hung on a spring balance mounted vertically in a lift. If the lift descends with an acceleration equal to the acceleration due to gravity $‘g’$, if the lift moves up with an acceleration equal to the acceleration due to gravity, the reading on the spring balance will be .......... $kg$
→There are two plane mirror with reflecting surfaces facing each other. The mirrors are moving with speed $v$ away from each other.$A$ point object is placed between the mirrors. The velocity of the $n$ -th image will be
→$A$ metallic rod of length $L$ and mass $M$ is moving under the action of two unequal forces $F_1$ and $F_2$ (directed opposite to each other) acting at its ends along its length. Ignore gravity and any external magnetic field. If specific charge of electrons is $(e/m)$, then the potential difference between the ends of the rod is steady state must be
→Two plane mirrors of length $L$ are separated by distance $L$ and $a$ man $M_2$ is standing at distance $L$ from the connecting line of mirrors as shown in figure. $A$ man $M_1$ is walking is a straight line at distance $2 L$ parallel to mirrors at speed $u$, then man $M_2$ at $O$ will be able to see image of $M_1$ for total time:
→A horizontal platform with an object placed on it is executing $S.H.M$. in the vertical direction. The amplitude of oscillation is $3.92 \times {10^{ - 3}}m$. What must be the least period of these oscillations, so that the object is not detached from the platform
→A girl brings a positively charged rod near a thin neutral stream of water from a tap. She observes that the water stream bends towards her. Instead, if she were to bring a negatively charged rod near to the stream, it will