A solenoid is $1.0$ $ metre$ long and it has $4250$ $turns$. If a current of $5.0$ $ampere$ is flowing through it, what is the magnetic field at its centre $[{\mu _0} = 4\pi \times {10^{ - 7}}\,weber/amp - m]$
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(b) Magnetic field at the centre of solenoid $(B) = {\mu _0}ni$
Where $n =$ Number of $turns /meter$
$\therefore \,B = 4\pi \times {10^{ - 7}} \times 4250 \times 5 = 2.7 \times {10^{ - 2}}\,Wb/{m^2}$
Where $n =$ Number of $turns /meter$
$\therefore \,B = 4\pi \times {10^{ - 7}} \times 4250 \times 5 = 2.7 \times {10^{ - 2}}\,Wb/{m^2}$
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