A solenoid is at potential difference $60\, V$ and current flows through it is $15$ ampere, then the resistance of coil will be ............ $\Omega$
A$4$
B$8$
C$0.25$
D$2$
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A$4$
a (a) ${\rm{Resistance}} = \frac{{{\rm{Potential}}\;{\rm{difference}}}}{{{\rm{Current}}}}$
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