Question
A solid metallic cuboid of dimensions $(9\ m \times 8\ m \times 2\ m)$ is melted and recast into solid cubes of edge $2\ m$. Find the number of cubes so formed.
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Answer
Volume of the solid metallic cuboid $=9 \mathrm{~m} \times 8 \mathrm{~m} \times 2 \mathrm{~m}=144 \mathrm{~m} 3$
Volume of each solid cube $=(\text { Edge })^3=(2)^3=8 \mathrm{~m}^3 \therefore$
Number of cubes formed $=\frac{\text { Volume of the solid metallic cuboid }}{\text { Volume of each solid cube }}=\frac{144}{8}=18$ Thus, the number of cubes so formed is $18.$
Volume of each solid cube $=(\text { Edge })^3=(2)^3=8 \mathrm{~m}^3 \therefore$
Number of cubes formed $=\frac{\text { Volume of the solid metallic cuboid }}{\text { Volume of each solid cube }}=\frac{144}{8}=18$ Thus, the number of cubes so formed is $18.$
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