A solid metallic sphere has a charge +3 Q. Concentric with this s… - Vidyadip

MCQ

A solid metallic sphere has a charge $+3 Q$. Concentric with this sphere is a conducting spherical shell having charge $-Q$. The radius of the sphere is ' $A$ ' and that of the spherical shell is ' $B$ ' $(B>A)$. The electric field at a distance 'R' (A < R < B) from the center is $\left(\varepsilon_0=\right.$ permittivity of vacuum $)$

A
$\frac{Q}{2 \pi \varepsilon_0 R}$
B
$\frac{3 Q}{2 \pi \varepsilon_0 R}$
✓
$\frac{3 Q}{4 \pi \varepsilon_0 R^2}$
D
$\frac{4 Q}{2 \pi \varepsilon_0 R^2}$

✓

Answer

Correct option: C.

$\frac{3 Q}{4 \pi \varepsilon_0 R^2}$

(c) : Electric field due to shell $=0$ Electric field due to sphere, $E=\frac{K 3 Q}{R^2}=\frac{3 Q}{4 \pi \varepsilon_0 R^2}$

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