MCQ
A solution has $pH = 5$, it is diluted $100 $ times, then it will become
- ✓Neutral
- BBasic
- CUnaffected
- DMore acidic
After dilution $[{H^ + }] = {10^{ - 5}}/100 = {10^{ - 7}}M$
$[{H^ + }]$ from ${H_2}O$ cannot be neglected.
Total $[{H^ + }] = {10^{ - 7}} + {10^{ - 7}} = 2 \times {10^{ - 7}}$
$pH = 7 - 0.3010 = 6.6990 = 7$(neutral).
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.
$(At. No. Ti = 22, V = 23, Cr = 24, Mn=25)$
| Column $I$ | Column $II$ |
| $(A)$ $Image$ | $(p)$ Racemic mixture |
| $(B)$ $Image$ | $(q)$ Addition reaction |
| $(C)$ $Image$ | $(r)$ Substitution reaction |
| $(D)$ $Image$ | $(s)$ Coupling reaction |
| $(t)$ Carbocation intermediate |

(Take: $\log 2=0.30 ; \log 2.5=0.40)$
$C{H_3} - C \equiv C - H\xrightarrow{{NaN{H_2}}}\xrightarrow{{C{H_3} - I}}(A)\xrightarrow{{Li/liq\,N{H_2}}}(B)$
$C{H_3} - C \equiv C - H\xrightarrow{{NaN{H_2}}}\xrightarrow{{C{H_3} - I}}(A)\xrightarrow[{Pd.CaC{O_3}}]{{{H_2}}}(C)$
