Question
A SONAR system fixed in a submarine operates at a frequency $40.0 kHz$ . An enemy submarine moves towards the $SONAR$ with a speed of $360 km h ^{-1}$. What is the frequency of sound reflected by the submarine? Take the speed of sound in water to be $1450 m s ^{-1}$.

Answer

The frequency of SONAR received by enemy submarine will be further reflected back to SONAR which it will receive again with a different frequency.
$SONAR$ frequency $(V_s) = 40kHz = 40 \times 10^3Hz$
Speed of enemy submarine($V_o$​​​​​​​) = 360km/h
$=360\times\frac{5}{18}=100\text{m/s}$
Speed of sound in water = 1450m/s
Apparent frequency received by submarine is
$\text{f}'=\Big\{\frac{\text{V}+\text{V}_\text{o}}{\text{V}}\Big\}\text{f}=\Big\{\frac{1450+100}{1450}\Big\}\times40=42.76\text{kHz}$
Now, the reflected wave have a different frequency,
$\text{f}"=\Big\{\frac{\text{V}}{\text{V}-\text{V}_\text{o}}\Big\}\text{f}'=\Big\{\frac{1450}{1450-100}\Big\}\times42.76=45.93\text{kHz}$

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