A source and an observer move away from each other with a velocity of $10\; m/s$ with respect to ground. If the observer finds the frequency of sound coming from the source as $1950 \;Hz$, then actual frequency of the source is .... $Hz$ (velocity of sound in air = $340\; m/s$)
AIIMS 2015, Medium
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$n' = n\,\left( {\frac{{v - {v_O}}}{{v + {v_S}}}} \right) = n\,\left( {\frac{{340 - 10}}{{340 + 10}}} \right) = 1950$
$ \Rightarrow $$n = 2068$$Hz$
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