A source of unknown frequency gives $4\,\, beats/s$ when sounded with a source of known frequency $250\,\, Hz.$ The second harmonic of the source of unknown frequency gives five beats per second, when sounded with a source of frequency $513\,\, Hz.$ The unknown frequency is .... $Hz$
AIPMT 2013, Medium
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Let $v$ be frequency of the unknown source.
As it gives 4 beats per second when sounded with a source of frequency $250 \mathrm{Hz}$
$\therefore \quad v=250 \pm 4=246 \mathrm{Hz}$ or $254 . \mathrm{Hz}$
Second harmonic of this unknown source$=492 \mathrm{Hz}$ or $508 \mathrm{Hz}$ which gives $5$ beats per second, when sounded with a source of frequency $513 \mathrm{Hz}$ Therefore unknown frequency, $v=254 \mathrm{Hz}$.
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