A transverse wave is given by $y = A\sin 2\pi \left( {\frac{t}{T} - \frac{x}{\lambda }} \right)$. The maximum particle velocity is equal to $4$ times the wave velocity when
A$\lambda = 2\pi A$
B$\lambda = \frac{1}{2}\pi A$
C$\lambda = \pi A$
D$\lambda = \frac{1}{4}\pi A$
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B$\lambda = \frac{1}{2}\pi A$
b (b) Given $A\omega = 4v \Rightarrow A2\pi n = 4n\lambda \Rightarrow \lambda = \frac{{\pi A}}{2}$
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$Assertion :$ For the formation of stationary waves the medium must be bounded having definite boundaries.
$Reason :$ In the stationary wave, some particles of the medium remain permanently at rest.
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