c
(c)
Pressure at bottom of sea $=\rho_w g h$
$\rho_w=1000 \,kg / m ^3=1 \,g / cc , \quad g=9.8 \,m / s ^2, h=1000 \,m$
$P=10^3 \times 9.8 \times 1000 \,N / m ^2$
$\text { Now } \frac{-\Delta V}{V}=\frac{P}{B} \quad\left\{\frac{-\Delta V}{V}=\frac{0.01}{100}\right. \text { (given) }$
$\frac{0.01}{100}=\frac{10^3 \times 9.8 \times 1000}{B}$
$B=9.8 \times 10^{10} \,N / m ^2$