Question
A wire of cross-sectional area $3\,m{m^2}$ is first stretched between two fixed points at a temperature of $20°C$. Determine the tension when the temperature falls to $10°C$. Coefficient of linear expansion $\alpha = {10^{ - 5}}   { ^\circ}{C^{ - 1}}$ and $Y = 2 \times {10^{11}}\,N/{m^2}$  ........ $N$

Answer

(c) $F = YA\alpha \Delta t$$ = 2 \times {10^{11}} \times 3 \times {10^{ - 6}} \times {10^{ - 5}} \times (20 - 10) = 60\,N$

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