A spherical conductor of radius $2m$ is charged to a potential of $120\, V$. It is now placed inside another hollow spherical conductor of radius $6m$. Calculate the potential to which the bigger sphere would be raised......$V$
A$20$
B$60$
C$80$
D$40$
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D$40$
d (d) If charge acquired by the smaller sphere is $Q$ then it’s potential $120 = \frac{{kQ}}{2}$ ..$ (i)$
Also potential of the outer sphere
$V = \frac{{kQ}}{6}$.....$(ii)$
From equation $(i)$ and $(ii)$ $V = 40\, volt$
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