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Two condensers ${C_1}$and ${C_2}$ in a circuit are joined as shown in figure. The potential of point $A$ is ${V_1}$ and that of $B$ is ${V_2}$. The potential of point $D$ will be
  • A$\frac{1}{2}({V_1} + {V_2})$
  • B$\frac{{{C_2}{V_1} + {C_1}{V_2}}}{{{C_1} + {C_2}}}$
  • C$\frac{{{C_1}{V_1} + {C_2}{V_2}}}{{{C_1} + {C_2}}}$
  • D$\frac{{{C_2}{V_1} - {C_1}{V_2}}}{{{C_1} + {C_2}}}$
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