MCQ
A spring having a spring constant $‘K’$ is loaded with a mass $‘m’$. The spring is cut into two equal parts and one of these is loaded again with the same mass. The new spring constant is
- A$\frac{K}{2}$
- B$K$
- ✓$2K$
- D${K^2}$
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.




$(A)$ The current through the circuit, $I$ is $0.3 \ A$
$(B)$ The current through the circuit, I is $0.3 \sqrt{2} \ A$.
$(C)$ The voltage across $100 \Omega$ resistor $=10 \sqrt{2} \ V$
$(D)$ The voltage across $50 \Omega$ resistor $=10 \ V$