A spring is compressed between two toy carts of mass m_1 and m_2.… - Vidyadip

MCQ

A spring is compressed between two toy carts of mass $m_1$ and $m_2$. When the toy carts are released, the springs exert equal and opposite average forces for the same time on each toy cart. If $v_1$ and $v_2$ are the velocities of the toy carts and there is no friction between the toy carts and the ground, then :

A
$v_1 / v_2=m_1 / m_2$
B
$v_1 / v_2=m_2 / m_1$
✓
$v _1 / v _2=- m _2 / m _1$
D
$v_1 / v_2=-m_1 / m_2$

✓

Answer

Correct option: C.

$v _1 / v _2=- m _2 / m _1$

c
(c)

Applying law of conservation of linear momentum

$m _1 v _1+ m _2 v _2=0$

$\frac{ m _1}{ m _2}=-\frac{ v _2}{ v _1} \text { or } \frac{ v _1}{ v _2}=-\frac{ m _2}{ m _1}$

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