A spring is stretched by $0.20\, m$, when a mass of $0.50\, kg$ is suspended. When a mass of $0.25\, kg$ is suspended, then its period of oscillation will be .... $\sec$ $(g = 10\,m/{s^2})$
Medium
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(b) Force constant $k = \frac{F}{x} = \frac{{0.5 \times 10}}{{0.2}} = 25\;N/m$
Now $T = 2\pi \sqrt {\frac{m}{k}} = 2\pi \sqrt {\frac{{0.25}}{{25}}} = 0.628\,sec$
Now $T = 2\pi \sqrt {\frac{m}{k}} = 2\pi \sqrt {\frac{{0.25}}{{25}}} = 0.628\,sec$
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