A spring is stretched by $5 \,\mathrm{~cm}$ by a force $10 \,\mathrm{~N}$. The time period of the oscillations when a mass of $2 \,\mathrm{~kg}$ is suspended by it is :(in $s$)
  • A$0.0628$
  • B$6.28$
  • C$3.14$
  • D$0.628$
NEET 2021, Medium
art

Download our app
and get started for free

Experience the future of education. Simply download our apps or reach out to us for more information. Let's shape the future of learning together!No signup needed.*

Similar Questions

  • 1
    The displacement of a particle is given at time $t$, by:$x=A \sin (-2 \omega t)+B \sin ^2 \omega t \quad$ Then,
    View Solution
  • 2
    The maximum acceleration of a particle in $SHM$ is made two times keeping the maximum speed to be constant. It is possible when
    View Solution
  • 3
    The maximum velocity of a particle, executing simple harmonic motion with an amplitude $7\ mm$, is $4.4\ m/s$. The period of oscillation is .... $sec$
    View Solution
  • 4
    Two pendulums of length $121\,cm$ and $100\,cm$ start vibrating in phase. At some instant, the two are at their mean position in the same phase. The minimum number of vibrations of the shorter pendulum after which the two are again in phase at the mean position is :
    View Solution
  • 5
    If the length of second's pendulum is decreased by $2\%$, how many seconds it will lose per day ...... $\sec$
    View Solution
  • 6
    A body is executing $S.H.M.$ When its displacement from the mean position is $4\, cm$ and $5\, cm$, the corresponding velocity of the body is $10 \,cm/sec$ and $8\, cm/sec$. Then the time period of the body is
    View Solution
  • 7
    The angular frequency of the damped oscillator is given by, $\omega  = \sqrt {\left( {\frac{k}{m} - \frac{{{r^2}}}{{4{m^2}}}} \right)} $ where $k$ is the spring constant, $m$ is the mass of the oscillator and $r$ is the damping constant. If the ratio $\frac{{{r^2}}}{{mk}}$ is $8\%$, the change in time period compared to the undamped oscillator is approximately as follows
    View Solution
  • 8
    Equations $y = 2A \cos ^2 \omega \,t$ and $y = A (\sin \omega t + \cos \omega t )$ represent the motion of two particles.
    View Solution
  • 9
    $Assertion :$ The time-period of pendulum, on a satellite orbiting the earth is infinity.
    $Reason :$ Time-period of a pendulum is inversely proportional to $\sqrt g$
    View Solution
  • 10
    Two particles oscillating in $SHM$ along two very close parallel path such that they have same mean position. The equation of $SHM$ of two particles are $x_1 = A\, sin\,\omega t$ and $x_2 = A\,sin(\omega t + \phi )$ respectively. If maximum distance between them is $\frac{6A}{5}$ then $\phi $ equal to ..... $^o$
    View Solution