Question
A spring-mass system oscillates with a frequency v. If it is taken in an elevator slowly accelerating upward, the frequency will:
  1. Increase.
  2. Decrease.
  3. Remain same.
  4. Become zero.

Answer

  1. Remain same.
Explanation:
Because the frequency $\Big(\text{v}-\frac{1}{2\pi}\sqrt{\frac{\text{k}}{\text{m}}}\Big)$ of the system is independent of the acceleration of the system.

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