$\Phi_{\text {through square }}=\mu_0 nI \times A \quad( A =\text { Area })$
$Emf =\mu_0 nA \times \frac{ dI }{ dt }$
$=\mu_0 n A \times I _0 \omega \cos \omega t$
$\text { Emf amplitude }=\mu_0 n A \times I _0 \omega$
$=4 \pi \times 10^{-7} \times \frac{50}{10^{-2}} \times 4 \times 10^{-4} \times 2.5 \times 700$
$=44 \times 10^{-4}\,V$
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$(i)$ third permitted energy level to the second level and $(ii)$ the highest permitted energy level to the second permitted level. The value of $x$ will be.
$(A)$ Radioactivity is a random and spontaneous process and is dependent on physical and chemical conditions.
$(B)$ The number of un-decayed nuclei in the radioactive sample decays exponentially with time.
$(C)$ Slope of the graph of $\log _{e}$ (no. of undecayed nuclei) $Vs$. time represents the reciprocal of mean life time $(\tau)$.
$(D)$ Product of decay constant ( $\lambda$ ) and half-life time $\left(T_{1 / 2}\right)$ is not constant.
Choose the most appropriate answer from the options given below
