$\mathrm{df}=\frac{2 \mathrm{f}_0 \mathrm{c}}{(\mathrm{c}-\mathrm{v})^2} \mathrm{dv}$
where $c$ is speed of sound
$\mathrm{df}=\frac{1.2}{100} \mathrm{f}_0$
hence $d v \approx 7 \mathrm{~km} / \mathrm{hr}$.
[Given: The speed of sound in air is $324 ms ^{-1}$ ]
($1$) When only $S_2$ is emitting sound and it is $Q$, the frequency of sound measured by the detector in $Hz$ is. . . . . .
($2$) Consider both sources emitting sound. When $S_2$ is at $R$ and $S_1$ approaches the detector with a speed $4 ms ^{-1}$, the beat frequency measured by the detector is $\qquad$ $Hz$.