A steel rod has a radius of $20\,mm$ and a length of $2.0\,m$. A force of $62.8\,kN$ stretches it along its length. Young's modulus of steel is $2.0 \times 10^{11}\,N / m ^2$. The longitudinal strain produced in the wire is $..........\times 10^{-5}$
JEE MAIN 2023, Easy
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$\text {Strain}=\frac{\text { stress }}{Y}=\frac{\frac{62.8 \times 10^3}{\pi \times(0.02)^2}}{2 \times 10^{11}}$
$=\frac{62.8 \times 10^3}{3.14 \times 4 \times 10^{-4} \times 2 \times 10^{11}}$
$=2.5 \times 10^{-4}$
$=25 \times 10^{-5}$
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