A steel rod is projecting out of rigid wall. The shearing strength of steel is $345 \,\,MN/m^2.$ The dimensions $AB = 5\,\, cm,\,BC = BE = 2\,\, cm.$ The maximum load that can be put on the face $ABCD$ is .......... $kg$ (neglect bending of the rod) $(g = 10\,\, m/s^2)$
Diffcult
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$345 \times 10^{6} \times 2 \times 10^{-2} \times 2 \times 10^{-2}=\mathrm{F}=\mathrm{mg}$
$13800 \mathrm{kg}=\mathrm{m}$
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