A steel wire of length $3.2 m \left( Y _{ S }=2.0 \times 10^{11}\,Nm ^{-2}\right)$ and a copper wire of length $4.4\,M$ $\left( Y _{ C }=1.1 \times 10^{11}\,Nm ^{-2}\right)$, both of radius $1.4\,mm$ are connected end to end. When stretched by a load, the net elongation is found to be $1.4\,mm$. The load applied, in Newton, will be. (Given $\pi=\frac{22}{7}$)
JEE MAIN 2022, Medium
Download our app for free and get started
$\Delta \ell_{1}+\Delta \ell_{2}=\Delta \ell$
$\frac{ F \ell_{1}}{ A _{1} y _{1}}+\frac{ F \ell_{2}}{ A _{2} y _{2}}=\Delta \ell$
$F =\frac{\Delta \ell}{\frac{\ell_{1}}{ A _{1} y _{1}}+\frac{\ell_{2}}{ A _{2} y _{2}}}=1.54 \times 10^{2}=154$
Download our appand get started for free
Experience the future of education. Simply download our apps or reach out to us for more information. Let's shape the future of learning together!No signup needed.*
Similar Questions
- 1A rubber cord $10\, m$ long is suspended vertically. How much does it stretch under its own weight $($Density of rubber is $1500\, kg/m^3, Y = 5×10^8 N/m^2, g = 10 m/s^2$$)$View Solution
- 2The graph shows the behaviour of a length of wire in the region for which the substance obeys Hook’s law. $P$ and $Q$ representView Solution
- 3A steel wire of diameter $0.5 mm$ and Young's modulus $2 \times 10^{11} N m ^{-2}$ carries a load of mass $M$. The length of the wire with the load is $1.0 m$. A vernier scale with $10$ divisions is attached to the end of this wire. Next to the steel wire is a reference wire to which a main scale, of least count $1.0 mm$, is attached. The $10$ divisions of the vernier scale correspond to $9$ divisions of the main scale. Initially, the zero of vernier scale coincides with the zero of main scale. If the load on the steel wire is increased by $1.2 kg$, the vernier scale division which coincides with a main scale division is. . . . Take $g =10 m s ^{-2}$ and $\pi=3.2$.View Solution
- 4View SolutionIf the temperature increases, the modulus of elasticity
- 5A wire of diameter $1mm$ breaks under a tension of $1000\, N.$ Another wire, of same material as that of the first one, but of diameter $2\, mm$ breaks under a tension of ...... $N$View Solution
- 6The elastic limit of brass is $3.5 \times 10^{10}\,N / m ^2$. Find the maximum load that can be applied to a brass wire of $0.75\,mm$ diameter without exceeding the elastic limit$.......\times 10^4\,N$View Solution
- 7If $x$ longitudinal strain is produced in a wire of Young's modulus $y,$ then energy stored in the material of the wire per unit volume isView Solution
- 8View SolutionWith rise in temperature, the Young's modulus of elasticity
- 9The work done in increasing the length of a metre long wire of cross-sectional area ........ $J.$ $1\,mm^2$ through $1\,mm$ will be $(Y = 2 \times 10^{11}\,Nm^{-2})$View Solution
- 10View SolutionThere are two wire of same material and same length while the diameter of second wire is two times the diameter of first wire, then the ratio of extension produced in the wires by applying same load will be