A stone is thrown at an angle to the horizontal reaches a maximum… - Vidyadip

MCQ

A stone is thrown at an angle $\theta $ to the horizontal reaches a maximum height $H$. Then the time of flight of stone will be

A
$\sqrt {\frac{{2H}}{g}} $
✓
$2\,\sqrt {\frac{{2H}}{g}} $
C
$\frac{{2\sqrt {2H\,\sin \theta } }}{g}$
D
$\frac{{\sqrt {2H\,\sin \theta } }}{g}$

✓

Answer

Correct option: B.

$2\,\sqrt {\frac{{2H}}{g}} $

b
(b) $H = \frac{{{u^2}{{\sin }^2}\theta }}{{2g}}$ and $T = \frac{{2u\sin \theta }}{g}$

$⇒$ ${T^2} = \frac{{4{u^2}{{\sin }^2}\theta }}{{{g^2}}}$

$\frac{{{T^2}}}{H} = \frac{8}{g}$

$⇒$ $T = \sqrt {\frac{{8H}}{g}} = 2\sqrt {\frac{{2H}}{g}} $

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