A storage battery is connected to a charger for charging with a voltage of $12.5\,\,Volts$. The internal resistance of the storage battery is $1\,\,\Omega$ . When the charging current is $0.5\,\,A$, the emf of the storage battery is: ............... $volts$
Medium
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Resistance of the charger,
$R=\frac{V}{I}$
$R=\frac{12.5}{0.5}=25 \Omega$
Now
$E=I R=\frac{V}{R+r}(R)$
$E=\frac{12.5}{25+1}(25)=(0.48)(25)=12 V$
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