MCQ
A straight line through the point $A (3, 4)$ is such that its intercept between the axes is bisected at $A$. Its equation is
- A$3x -4y + 7 = 0$
- ✓$4x + 3y = 24$
- C$3x + 4y = 25$
- D$x + y = 7$
$\frac{a+0}{2}=3=>a=6$
$\frac{0+b}{2}=4=>b=8$
Equation of the line is $\frac{x}{6}+\frac{y}{8}=1$
$\frac{4 x+3 y}{24}=1$
$4 x+3 y=24$
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.