MCQ
A string is producing transverse vibration whose equation is $y = 0.021\;\sin (x + 30t)$, Where $x$ and $y$ are in meters and $t$ is in seconds. If the linear density of the string is $1.3 \times {10^{ - 4}}\,kg/m,$ then the tension in the string in $N$ will be
  • A
    $10$
  • B
    $0.5$
  • C
    $1$
  • $0.12$

Answer

Correct option: D.
$0.12$
d
(d) $y = 0.021\sin (x + 30t)$==> $v = \frac{\omega }{k} = \frac{{30}}{1} = 30\,m/s$. 

Using, $v = \sqrt {\frac{T}{m}} \Rightarrow 30 = \sqrt {\frac{T}{{1.3 \times {{10}^{ - 4}}}}} \Rightarrow T = 0.117\,N$

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