A student determined Young's Modulus of elasticity using the formula $Y=\frac{M g L^{3}}{4 b d^{3} \delta} .$ The value of $g$ is taken to be $9.8 \,{m} / {s}^{2}$, without any significant error, his observation are as following.

Physical Quantity Least count of the Equipment used for measurement Observed value
Mass $({M})$ $1\; {g}$ $2\; {kg}$
Length of bar $(L)$ $1\; {mm}$ $1 \;{m}$
Breadth of bar $(b)$ $0.1\; {mm}$ $4\; {cm}$
Thickness of bar $(d)$ $0.01\; {mm}$ $0.4 \;{cm}$
Depression $(\delta)$ $0.01\; {mm}$ $5 \;{mm}$

Then the fractional error in the measurement of ${Y}$ is

  • A$0.0083$
  • B$0.0155$
  • C$0.155$
  • D$0.083$
JEE MAIN 2021, Diffcult
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