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If in a Vernier callipers $10 \,VSD$ coincides with $8 \,MSD$, then the least count of Vernier calliper is ............ $m$  [given $1 \,MSD =1 \,mm ]$
  • A$1 \times 10^{-4}$
  • B$2 \times 10^{-4}$
  • C$1 \times 10^{-3}$
  • D$8 \times 10^{-4}$
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