A student in the laboratory measures thickness of a wire using screw gauge. The readings are $1.22\,mm , 1.23\,mm , 1.19\,mm$ and $1.20\,mm$. The percentage error is $\frac{ x }{121} \%$. The value of $x$ is ..............
A$100$
B$150$
C$98$
D$140$
JEE MAIN 2022, Medium
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B$150$
b $X =\frac{1.22 mm +1.23 mm +1.19 mm +1.20 mm }{4}$
$X =1.21 mm$
$\Delta x =\frac{0.01+0.02+0.02+0.01}{4}=\frac{0.06}{4}=0.015$
Percentage error $=\frac{0.015}{1.21} \times 100$
$X =150$
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