MCQ
A suitable unit for gravitational constant is
- A$kg{\rm{ - }}\,m\;{\sec ^{ - 1}}$
- B$N\;{m^{ - 1}}\sec $
- ✓$N\,\,{m^2}\,k{g^{ - 2}}$
- D$kg\,m\,{\sec ^{ - 1}}$
✓
Answer
Correct option: C.
$N\,\,{m^2}\,k{g^{ - 2}}$
c
(c) $F = \frac{{G{m_1}{m_2}}}{{{d^2}}};$
(c) $F = \frac{{G{m_1}{m_2}}}{{{d^2}}};$
$\therefore $ $G = \frac{{F{d^2}}}{{{m_1}{m_2}}} = N{m^2}/k{g^2}$
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