MCQ
A table top is semicircular in shape with diameter $2.8m$. Area of this table top is:
  • $3.08 \mathrm{~m}^2$
  • B
    $6.16 \mathrm{~m}^2$
  • C
    $12.32 \mathrm{~m}^2$
  • D
    $24.64 \mathrm{~m}^2$

Answer

Correct option: A.
$3.08 \mathrm{~m}^2$
Given, diameter $= 2.8m$
Now, radius $=\frac{2.8}{2}\text{m}=1.4\text{m}$ $\big[\because\text{radius}=\frac{\text{diameter}}{2}\big]$
$\therefore$ Area of table top = Area of semi-circle
$=\frac{\pi\text{r}^2}{2}=\frac{22}{7}\times\frac{1.4}{2}\times1.4=3.08\text{m}^2$

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